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* Is it possible to get all 52 cards to the homecellsatonce?Yes. While I was participating in Dave Ring's project, I noted thatsome deals ended with 40 or more cards going to the homecells at theend of the game (called a flourish, cascade, or sweep -- the latterterm coming from peg solitaire). The best I managed was 47 cards.George W. Edman discovered a number of deals on which he could end witha 50-card flourish: 7329, 7851, 15824, 23600, 26963, 31126 (found byCarol Philo), and 31637. Edman's solution to 7851, remarkably short at35 moves, is found in the solution catalog. Since the standard versionof FreeCell plays aces automatically to the homecells as soon as theyare available, these deals depend on having two aces buried at thebottom of the same column, and arranging the remaining cards intosequence before uncovering the last two aces. But in March of 1998,Andy Gefen found the ultimate: a 52-card flourish. After noticing thatdeal number 18492 had four aces at the bottom ofcolumn six, he realized that if he could get all of the other cards inorder without moving the seven of diamonds which covers the aces, hecould achieve the 52-card flourish! He was able to do so afterconsiderable effort, and his solution is now available in the solution catalog. Dave Leonard laterfound a second 52-card flourish, 22574 (with a different arrangement ofaces), and a 51-card flourish, 765. Brian Barnhorst found a third52-card flourish, 7239, Dave found a fourth, 23190, and Kenneth Goldmanfound a fifth, 16508. All of the solutions to these 52-card flourishesare found in the catalog. Ben Johannesen found five more, 9993, 10331,12387, 17502, and 27251. Jason A. Crupper found 18088, and then usedJim Horne's dealing code to write a program to search the 32,000standard deals for more candidates. He found six more for which he wasable to find solutions: 7321, 8536, 16371, 28692, 29268, and 29640.This brings the total to seventeen. Jason found two otherpossibilities, but writes: "14150 and 26852 have the right setup ofaces, but also present extreme strategical difficulties, enough that Isuspect that they are unsolvable, in the same way that 11982 isunsolvable". Danny A. Jones's solver confirms that those twodeals are impossible as 52-card flourishes. 2ff7e9595c
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